Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 *V*.

Advertisement Remove all ads

#### Solution

Given Charge, Q = 96000C

Time, *t*= 1hr = 60 x 60= 3600s

Potential difference, *V*= 50volts

Now we know that *H*= VIt

So we have to calculate *I* first

As *I*= Q/*t*

∴ I = 96000/3600 = 80/3 A

H=50 x 80/3 x 60 x 60=4.8 x 10 ^{6j}

Therefore, the heat generated is 4.8 x 10^{6} J.

Concept: Effects of Electric Current - Heating Effect of Electric Current

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads